Ideal gas law
P V = n R TR = 8.314462618 J/(mol·K)
Solve for
Reference conditions
From a mass (optional)
g
1 mol of the gas at 0 °C under 1 atm occupies 22.41 L.
In kelvin 273.15 K
P V = n R TR = 8.314462618 J/(mol·K)
Solve for
Reference conditions
From a mass (optional)
1 mol of the gas at 0 °C under 1 atm occupies 22.41 L.
In kelvin 273.15 K